25x=3x^2

Solution for 25x=3x^2 equation:

25x=3x^2

We move all terms to the left:

25x-(3x^2)=0

determiningTheFunctionDomain
-3x^2+25x=0

a = -3; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-3)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-3}=\frac{-50}{-6}
=8+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-3}=\frac{0}{-6}
=0
$